V=4/3 πr^3would be the formula
{\text{Direction of parabola depends on the sign of quadratic coefficient of a }} \hfill \\
{\text{quadratic equation}}. \hfill \\
{\text{For given quadratic equation}}. \hfill \\
a{x^2} + bx + c = 0 \hfill \\
{\text{The parabola is in the upward direction if }}a{\text{ }} > {\text{ }}0{\text{ and in downward direction if }}a < 0 \hfill \\
{\text{Here, the equation of given parabola is }} \hfill \\
{x^2} - 6x + 8 = y \hfill \\
\Rightarrow y = \left( {{x^2} - 6x + 9} \right) - 9 + 8 \hfill \\
\Rightarrow y = {\left( {x - 3} \right)^2} - 1. \hfill \\
{\text{Thus, the parabola is in the upward direction}} \hfill \\
Answer:
the solution for x will be given by {x| -13 < x < 13}
Therefore the correct option is B.
Step-by-step explanation:
i) given that |x| < 13
ii) therefore x < 13 for positive values of x
iii) for negative values of x we have -x < 13
therefore x > -13
iv) from ii) and iii) above we can conclude that the solution for x will be given by {x| -13 < x < 13}
Therefore the correct option is B.
Answer:
99.9
Step-by-step explanation:
