ANSWER QUICK PLSS!!!

Refer to the table above. Which event is independent of gender?

N76 [4]

Answer:

A randomly chosen female voter is Other.

Step-by-step explanation:

Well, you just have to read it and ask yourself which one is specific to only one gender, or which one talks about only one gender, so the answer here is:

A randomly chosen female voter is Other.

5 0

2 years ago

Will give brainliest to good answer

kakasveta [241]

Here are some notes i have from some sources i hope these notes will be able to help you achieve the grade you wanted to good luck!

-The bound on error of estimation, B , associated with a confidence interval is (z critical value) ·(standard error of the statistic) . ... Sample Size The sample size required to estimate a population proportion  to within an amount B with 95% confidence is The value of  may be estimated by prior information.

-P-value and margin of error are not same.

-A margin of error tells you how many percentage points your results will differ from the real population value. For example, a 95% confidence interval with a 4 percent margin of error means that your statistic will be within 4 percentage points of the real population value 95% of the time.

-The margin of error determines how reliable the survey is or how reliable the results of the experiment are. ... This is captured in statistics as margin of error. The higher the margin of error, the less likely it is that the results of the survey are true for the whole population.

-Population distribution means the pattern of where people live. World population distribution is uneven. Places which are sparsely populated contain few people. Places which are densely populated contain many people.

These notes are from sources found online not mine If you want the sites just comment and ill give you them!

8 0

2 years ago

Find the minimum and maximum of f(x,y,z)=x^2+y^2+z^2 subject to two constraints, x+2y+z=4 and x-y=8.

Alika [10]

The Lagrangian for this function and the given constraints is

$L(x,y,z,\lambda_1,\lambda_2)=x^2+y^2+z^2+\lambda_1(x+2y+z-4)+\lambda_2(x-y-8)$

which has partial derivatives (set equal to 0) satisfying

$\begin{cases}L_x=2x+\lambda_1+\lambda_2=0\\L_y=2y+2\lambda_1-\lambda_2=0\\L_z=2z+\lambda_1=0\\L_{\lambda_1}=x+2y+z-4=0\\L_{\lambda_2}=x-y-8=0\end{cases}$

This is a fairly standard linear system. Solving yields Lagrange multipliers of $\lambda_1=-\dfrac{32}{11}$ and $\lambda_2=-\dfrac{104}{11}$ , and at the same time we find only one critical point at $(x,y,z)=\left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right)$ .

Check the Hessian for $f(x,y,z)$ , given by

$\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}$

$\mathbf H$ is positive definite, since $\mathbf v^\top\mathbf{Hv}>0$ for any vector $\mathbf v=\begin{bmatrix}x&y&z\end{bmatrix}^\top$ , which means $f(x,y,z)=x^2+y^2+z^2$ attains a minimum value of $\dfrac{480}{11}$ at $\left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right)$ . There is no maximum over the given constraints.

7 0

3 years ago

The tables show the high and low temperatures in Chicago over a 15-day period. Which set of data has the greatest RANGE?

tensa zangetsu [6.8K]

I would say the low I’m just guessing so get it checked

8 0

2 years ago

Read 2 more answers

Which of the following relations are not functions? Select all that apply.  {(1, 3), (3, 7), (5, 11), (7, 15), (9, 19)}  {(1,

zavuch27 [327]

Given:

7 relations are given.

To find:

The relation which is not a function.

Step-by-step explanation:

A relation is called function if there exist unique output for each input.

It means, each x-value has only one y-value.

{(1, 3), (3, 7), (5, 11), (7, 15), (9, 19)}, it is a function.

{(1, 3), (1, 7), (5, 11), (5, 15), (9, 19)}, it is not a function because there exist two y-values y=3 and y=7 at x=1.

{(−2, 4), (−1, 1), (0, 0), (1, 1), (2, 4)}, it is a function.

{(2, 4), (1, 1), (0, 0), (1,−1), (2, −4)},it is not a function because there exist two y-values y=4 and y=-4 at x=2.

{(6, 3), (4, 1), (2, 1), (0,−1), (−2,−3)}, it is a function.

{(1, 3), (3, 7), (3, 11), (7, 15), (9, 19)}, it is not a function because there exist two y-values y=7 and y=11 at x=3.

{(1, 3), (3, 7), (5, 11), (9, 15), (9, 19)}, it is not a function because there exist two y-values y=15 and y=19 at x=9.

Therefore, the correct options are 2, 4, 6 and 7.

8 0

2 years ago