Because of the fact that the amberjack is essentially three snappers, it can be shown as 3s
since one snapper is one s, and the amberjack is 3s, we can combine like terms
s+3s = 4s
because altogether, the fish weigh 44 pounds, 4s would equal 44 (shown as 4s = 44), from there, simply divide by 4 on both sides to get the weight of a snapper;
s = 11
Small bonus (finding an amberjack)
Since an amberjack is equal to three snappers, and a snapper is 11 pounds, an amberjack would be 33 pounds.
Subtract magazine from total:
25 -5 = 20
Divide by number of erasers:
20/4 = 5
Each eraser cost $5
Answer:
Step-by-step explanation:
11
Answer:
14.6
Step-by-step explanation:
It is given that,
The average weight of the top 5 fish caught at a fishing tournament was 12.3 pounds. From the attached figure, the weight of 5 fish are given. We need to find the weight of Wayne S. fish.
Average = sum of terms/no of terms
Let the weight of Wayne S. is x. So,
Here the sum of terms is x+12.8+12.6+11.8+9.7 and the number of terms is 5.
So, the weight of the heaviest fish is 14.6.
C
-x=-y-10 = x=y+10
x is 10 bigger than y
x+y=12
C