We write to expressions since there are two unknown here which is x and y. The first expression is the <span>sum of two numbers, x and y, is 12.
x + y = 12
The second expression is that the </span><span>difference of x and two times y is 6.
x -2y = 6
Therefore, the values of x and y are 10 and 2.</span>
A, B, and D? I chose those 3 because they all feature the expression a. (I literally just signed up, sorry, I'm still kind of new.)
Answer:
13+4=17,17/64=3-8=-5
Step-by-step explanation:
this is the solution
I believe it would be 45 is greater than or equal to 3x + (3x-1) + [(3x-1)-4]
X - y = 7.....x = y + 7
x * y = 60
y(y + 7) = 60
y^2 + 7y = 60
y^2 + 7y - 60 = 0
(y + 12)(y - 5) = 0
y + 12 = 0
y = -12....not this one because it is negative
y - 5 = 0
y = 5 <===
x - y = 7
x - 5 = 7
x = 7 + 5
x = 12 <==
so ur 2 numbers are 12 and 5
