Answer:
0.005 M
Explanation:
Given data:
volume of sample solution ( volume of D ) = 5.0 mL
volume of added stock solution ( V1 ) = 5.0 mL
concentration of added stock solution ( N1 ) = 0.02 M
Total volume of concentration ( V2 )= 10 mL = ( 5.0 mL + 5.0mL)
concentration of Total volume of sample ( C2 ) = 0.01
N2 = ( N1V1 ) / V2
= ( 0.02 * 5 ) / 10 = 0.01 m
absorbance of sample solution ( A1 ) = 0.10
absorbance of additional sample solution ( A2 ) = 0.20
attached below is the remaining part of the detailed solution
Nascent oxygen has much higher reactivity than the oxygen bubbled through the reaction mixture. It doesn't stay nascent for long (you are right about it being converted quick to just O2), which is why it has to be generated in situ
Answer:
Dalton law states that the partial pressure of a gas in a mixture of gases is equal to the total pressure of the mixture.
Given parameters:
Volume of CuSO₄ = 250mL
Concentration of CuSO₄ = 2.01M
Unknown:
Mass of CuSO₄.5H₂O = ?
To solve this problem, we must write the chemical relationship between both species.;
CuSO₄.5H₂O → CuSO₄ + 5H₂O
Now that we know the expression, it is possible to solve for the unknown mass.
First find the number of moles of CuSO₄;
Number of moles = Concentration x Volume
Take 250mL to L so as to ensure uniformity of units;
Volume = 250 x 10⁻³L
Input the parameters and solve for number of moles;
Number of moles = 250 x 10⁻³ x 2.01 = 0.5mol
From the equation;
1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O
So 0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O
Now let us find the molar mass of CuSO₄.5H₂O = 63.6 + 32 + 4(16) + 5(2x1 + 16) = 249.6g/mole
Mass of CuSO₄.5H₂O = number of moles x molar mass
= 0.5 x 249.6
= 124.8g
The mass of CuSO₄.5H₂O is 124.8g
Answer:
Explanation:
In a chemical formula, the oxidation state of transition metals can be determined by establishing the relationships between the electrons gained and that which is lost by an atom.
We know that for compounds to be formed, atoms would either lose, gain or share electrons between one another.
The oxidation state is usually expressed using the oxidation number and it is a formal charge assigned to an atom which is present in a molecule or ion.
To ascertain the oxidation state, we have to comply with some rules:
- The algebraic sum of all oxidation numbers of an atom in a neutral compound is zero.
- The algebraic sum of all the oxidation numbers of all atoms in an ion containing more than one kind of atom is equal to the charge on the ion.
For example, let us find the oxidation state of Cr in Cr₂O₇²⁻
This would be: 2x + 7(-2) = -2
x = +6
We see that the oxidation number of Cr, a transition metal in the given ion is +6.
