<h2>The graph of y = ax^2 + bx + c
</h2><h2>A nonlinear function that can be written on the standard form
</h2><h2>ax2+bx+c,where a≠0
</h2><h2>All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is
</h2><h2>
y=x2
</h2><h2>
The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate
</h2><h2>x=−b2a
</h2><h2>The y-coordinate of the vertex is the maximum or minimum value of the function.
</h2><h2>a > 0 parabola opens up minimum value
</h2><h2>a < 0 parabola opens down maximum value
</h2><h2>
A rule of thumb reminds us that when we have a positive symbol before x2 we get a happy expression on the graph and a negative symbol renders a sad expression.
</h2><h2>The vertical line that passes through the vertex and divides the parabola in two is called the axis of symmetry. The axis of symmetry has the equation
</h2><h2>x=−b2a
</h2><h2>The y-intercept of the equation is c.
</h2><h2>
When you want to graph a quadratic function you begin by making a table of values for some values of your function and then plot those values in a coordinate plane and draw a smooth curve through the points.</h2>
Answer:
I,R,I,I,R,I,R,R,I,R,I,R,I,I,R,R,I,I,I,I
Step-by-step explanation:
There’s are ratio which would be 8/10. 12/x should equally 8/10. So it would be 14 tiles long.
Point slope form
y-y1=m(x-x1)
slope=m
a point is (x1,y1)
slope=(y2-y1)/(x2-x1)
given
(-6,4) and (2,0)
slope=(0-4)/(2-(-6))=-4/(2+6)=-4/8=-1/2
a point is (-6,4)
x1=-6
y1=4
y-4=-1/2(x+6)
not listed
