Hey!!
here is your answer >>>
1) 3x - 10 > 11
let's take this as 3x - 10 = 11
3x = 21
x = 7
So, The numbers of X are always more than 7
2) 9x + 2 < 5
9x + 2 = 5
9x = 3
x = 1÷2
The numbers of X are always less than 1 ÷ 2
3) 2x + 8 < 6
2x + 8 = 6
2x = 2
x = 1
The numbers of X are less than 1
4) 4x - 3 < 12
4x - 3 = 12
4x = 15
x = 15 ÷ 4
The numbers of X are less than 15 ÷ 4
5) 2 ( 9 + x ) > 20
2 ( 9 + x ) = 20
9 + x = 10
x = 1
The numbers of X are more than 1
We can solve the rest using this
Hope my answer helps!
I believe it may be C. Because, the color changing has nothing to do with the reaction you get.
The expression that would be added to both sides is (b/2a)^2
<h3>How to determine the expression?</h3>
The equation is given as:
x^2 + b/ax + __ = c/a + __
Take the coefficient of x
b/a
Divide by 2
b/2a
Square the expression
(b/2a)^2
Hence, the expression that would be added to both sides is (b/2a)^2
Read more about quadratic equation at:
brainly.com/question/10449635
#SPJ1
Answer:
No te gustará cuando la gente te haga la vida tan difícil (:
Jus remeber karama todavía está viva
