We can plug those values into the equation, and if the answer is incorrect, we'll know if either one is extraneous.
√11 - 2(-7) = √(-7)^2 + 4(-7) + 4
√25 = √25
5 = 5
The first solution, -7, makes the equation true, and so it is not extraneous.
√11 - 2(1) = √(1)^2 + 4(1) + 4
√9 = √9
3 = 3
The second solution, 1, makes the equation true, and so it is also not extraneous.
<h3>The correct option is D, neither solution is extraneous. </h3>
First, distribute the (1/2) into (4x+12) by multiplying them.
The equation becomes:
2x + 6 + 5x = 30
On the left side, combine “like terms” through addition.
7x + 6 = 30
Subtract 6 from both sides:
7x = 24
Finally, get x alone by dividing both sides by 7:
x = 24/7, or if you wanted to round the decimal answer, it’s about 3.429.
Answer:
They would never intersect because they are parallel lines. You can tell they are parallel lines because they have the same slope and they have a different y-intercept. However, this doesn't mean that there was no solutions, there were, thats how i was able to tell what their slopes and y-intercepts were. So if there is an answer that you can choose from that explains that they won't intersect because they are parallel then that is the correct answer. It may be C, but I would see if there is another option.
Answer:
70 yd.
Step-by-step explanation:
The three streets at the intersection form a right triangle.
For a right triangle, the length of the longest side (called hypothenuse) is given by Pythagorean's theorem:
where
x is the length of the 1st side
y is the length of the 2nd side
h is the length of the hypothenuse
Here we want to find the hypothenuse.
We have:
x = 42 yd (length of the 1st side)
y = 56 yd (length of the 2nd side)
Substituting, we find h:
