Answer:
the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Step-by-step explanation:
since the volume of a cylinder is
V= π*R²*L → L =V/ (π*R²)
the cost function is
Cost = cost of side material * side area + cost of top and bottom material * top and bottom area
C = a* 2*π*R*L + b* 2*π*R²
replacing the value of L
C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²
then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then
dC/dR = -2*a*V/R² + 4*π*b*R = 0
4*π*b*R = 2*a*V/R²
R³ = a*V/(2*π*b)
R= ∛( a*V/(2*π*b))
replacing values
R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm
then
L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm
therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Volume of a cone is 1/3 of the area of the base times the height
v=(1/3)pi*5*5*18=(1/3)pi815*15*h
h=2
The answer is 50% hope this helps
The answer is going to 328.5 or 328.50 is the same thing
Answer:
(n-2)180 (this is the equation to find the sum of interior angles)
(4-2) 180 (plug in the amount of angles in the polygon and then solve)
2* 180
360
360 - 115 -100- 73= 72 (360 is the sum of all angles for this polygon. so subtract the known angles to find the unknown one)
measure of angle B is 72 degrees
Step-by-step explanation:
