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2 years ago

How do I solve this using the Pythagorean theorem

Mathematics

1 answer:

charle [14.2K]2 years ago

3 0

Answer:

x=3

Step-by-step explanation:

First would need to convert the radical into a number.

And since if you have a perfect square of a radical it goes outside the square root sign, you would take the 3 and square it to make 9 and then take the 2 inside the square root sign and multiply so you have the square root of 18|

Since we have $\sqrt{18}$ as the Leg c we would need to square it, squaring a square root sign would just cause them to be cancelled out and you being left with 18, afterwards find the square of 3, which is 9

18-9=9

square root of 9 = 3

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LaTeX: \sqrt[]{36} 36 2) LaTeX: \sqrt[3]{-8} − 8 3 3) LaTeX: -\sqrt[]{100} − 100 4) LaTeX: \sqrt[3]{27} I'm sorry that's the bes

Mamont248 [21]

Given:

Consider the expression are

1) $\sqrt{36}$

2) $\sqrt[3]{-8}$

3) $-\sqrt{100}$

4) $\sqrt[3]{27}$

To find:

The simplified form of each expression.

Solution:

1. We have,

$\sqrt{36}=\sqrt{6^2}$

$\sqrt{36}=6$

Therefore, the value of this expression is 6.

2. We have,

$\sqrt[3]{-8}=(-8)^{\frac{1}{3}}$

$\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}$

$\sqrt[3]{-8}=(-2)^{\frac{3}{3}}$

$\sqrt[3]{-8}=-2$

Therefore, the value of this expression is -2.

3. We have,

$-\sqrt{100}=-\sqrt{10^2}$

$-\sqrt{100}=-10$

Therefore, the value of this expression is -10.

4. We have,

$\sqrt[3]{27}=(27)^{\frac{1}{3}}$

$\sqrt[3]{27}=(3^3)^{\frac{1}{3}}$

$\sqrt[3]{27}=(3)^{\frac{3}{3}}$

$\sqrt[3]{27}=3$

Therefore, the value of this expression is 3.

3 0

2 years ago

Help I need it now!!<br> T14= 46, and t20= 100, find t3, t7, and tn

Vinil7 [7]

Answer:

$t_3 = -53\\\\\\t_7 = -17\\t_n= -80 +9n$

Step-by-step explanation:

Arithmetic sequence:

$\sf \boxed{t_n=a+(n-1)d}$

Here a is the first term and d is the common difference.

$t_{14}= 6$ ⇒ $\sf a + 13 d = 46$ ------------(I)

$\sf t_{20} = 100$ ⇒ a + 19d = 100 ---------(II)

Subtract equation (I) from (II)

(I1) a + 19d = 100

(II) a + 13d = 46

6d = 54

d = 54 ÷ 6

$\sf \boxed{d = 9}$

Substitute d = 9 in equation(I) and find 'a',

a + 13*9= 46

a + 117 = 46

a = 46 - 117

a = -71

$\sf t_3 = -71 + 2*9$

= -71 + 18

= -53

$\sf t_7 = -71 + 6*9$

= -71 + 54

= -17

$\sf t_n= -71 + (n-1)*9$

= -71 + 9*n - 1 *9

= -71 + 9n - 9

= -71 - 9 + 9n

= - 80 + 9n

5 0

8 months ago

If f(x)=2x-5, which expression represents f(x+1)? A) 2x-3, B) 2x-4, C)2x-5, D)2x+7

Dovator [93]

F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.

5 0

2 years ago

Need this asap please

Reptile [31]

Answer:

Third one is correct because it says it must be more than 2 not 2 or more.

The one you choose would be like, it must be 2 or more.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I need the function for the volume of the box for number 1

rjkz [21]

Answer:

Step-by-step explanation:

The volume of a rectanguiar shape like this one is V = L * W * H, where the letters represent Length, Width and Height. Here L is the longest dimension and is 28 - 2x; W is the width and is 22-2x; and finally, x is the height. Thus, the volume of this box must be

V(x) = (28 - 2x)*(22 - 2x)*x

and we want to maximize V(x).

One way of doing that is to graph V(x) and look for any local maximum of the graph. We'd want to determine the value of x for which V(x) is a maximum.

Another way, for those who know some calculus, is to use the first and second derivatives to identify the value of x at which V is at a maximum.

I have provided the function that you requested. If you'd like for us to go all the way to a solution, please repost your question.

3 0

1 year ago

How do I solve this using the Pythagorean theorem​

How do I solve this using the Pythagorean theorem