1. From grams -> mole:
=grams given x 1 mol/molar mass
So 150 g Cu x 1 mol Cu/63.546 g Cu = 2.4 mol Cu
2. From mole -> atoms
=number of mol x 6.022x10^22 atoms/1 mol
So 2.4 mol Cu x 6.022x10^22 atoms Cu/1 mol Cu = 1.4 x 10^24 atoms Cu
Each element<span> can usually be classified as a metal or a non-metal based on their ... They are usually </span>dull<span>and therefore show no metallic </span>luster<span> and they do not reflect ... </span>Dull<span>, Brittle solids; Little or no metallic </span>luster<span>; </span>High<span> ionization energies; </span>High<span> ...</span>
Answer:
During nuclear fission and fusion matter that seems to disappear but is actually converted into energy. The amount of energy (E) produced in such a reaction can be calculated using Einstein's formula for the equivalence of mass and energy: E = mc^2.
Explanation:
Answer:
Explanation:
Hello,
In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:
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Explanation:
1. Attachment
Electron dot structure of H2S (hydrogen sulfide)
2. Attachment
Electron dot structure of F2 (Fluorine).
