The answer would be B. symmetric property
Answer:
I think that's right. I checked my answer and proved it on that sheet.
Step-by-step answer:
Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals
Ra = 2Fcos(a) ..............................(1)
Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals
Rb = 2Fcos(b)..............................(2)
We are given that
Ra = 2Rb ....................................(3)
Substitute (1) & (2) in (3) gives
2Fcos(a) = 2(2Fcos(b))
Expand
2Fcos(a) = 4Fcos(b)
Simplify
cos(a) = 2 cos(b) QED
Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.
Have a nice day!
Answer:
-10
Step-by-step explanation:
6=-x-4 plug in 6 for f(x)
10=-x add 4 to both sides in order to cancel out the -4
-10=x multiple each side by -1 to make the x positive
Make denominator common,
1/27 - 27/27 = (1-27)/27 = -26/27