Answer:
The gcf of 15 and 64 can be obtained like this: The factors of 15 are 15, 5, 3, 1. The factors of 64 are 64, 32, 16, 8, 4, 2, 1. The common factors of 15 and 64 are 1, intersecting the two sets above. In the intersection factors of 15 ∩ factors of 64 the greatest element is 1. Therefore, the greatest common factor of 15 and 64 is 1.
Hope this helped!
Good luck :p
~Emmy <3
<span>Length = 1200, width = 600
First, let's create an equation for the area based upon the length. Since we have a total of 2400 feet of fence and only need to fence three sides of the region, we can define the width based upon the length as:
W = (2400 - L)/2
And area is:
A = LW
Substitute the equation for width, giving:
A = LW
A = L(2400 - L)/2
And expand:
A = (2400L - L^2)/2
A = 1200L - (1/2)L^2
Now the easiest way of solving for the maximum area is to calculate the first derivative of the expression above, and solve for where it's value is 0. But since this is supposedly a high school problem, and the expression we have is a simple quadratic equation, we can solve it without using any calculus. Let's first use the quadratic formula with A=-1/2, B=1200, and C=0 and get the 2 roots which are 0 and 2400. Then we'll pick a point midway between those two which is (0 + 2400)/2 = 1200. And that should be your answer. But let's verify that by using the value (1200+e) and expand the equation to see what happens:
A = 1200L - (1/2)L^2
A = 1200(1200+e) - (1/2)(1200+e)^2
A = 1440000+1200e - (1/2)(1440000 + 2400e + e^2)
A = 1440000+1200e - (720000 + 1200e + (1/2)e^2)
A = 1440000+1200e - 720000 - 1200e - (1/2)e^2
A = 720000 - (1/2)e^2
And notice that the only e terms is -(1/2)e^2. ANY non-zero value of e will cause this term to be non-zero and negative meaning that the total area will be reduced. Therefore the value of 1200 for the length is the best possible length that will get the maximum possible area.</span>
Answer:
b. 21
Step-by-step explanation:
The first five mutiples of 7 are:<em> 7, 14, 21, 28, 35. </em>You can get these by multiplying 7 to any integer.
- 7x1 = 7
- 7x2 = 14
- 7x3 = 21
- 7x4 = 28
- 7x5 = 35
In order to get the average of these numbers, you have to add them and divide the sum to the total number of multiples.
Let's add first.
7+14+21+28+35 = 105
Let's divided 105 by 5, which is the number of the multiples of 7.
105÷5 = 21
<em>The answer is 21.</em>