Answer:
Step-by-step explanation:
a1 = - 2
an = a1 * r^(n - 1)
a6 = -486
-486 = - 2 * r^(6-1) Divide by 2
243 = r^5
The largest value that r could be is 3.
4^5 = 1024
(243)^(1/5) = 3
So the general formula
an = -2*(3)^(n - 1)
Answer:
- 273 mL of 5%
- 117 mL of 15%
Step-by-step explanation:
Let q represent the quantity of 15% dressing used. Then the amount of 5% dressing is (390 -q). The amount of vinegar in the mix is ...
0.15q + 0.05(390 -q) = 0.08(390)
0.10q = 31.2 -19.5 = 11.7 . . . . . . subtract 0.05(390) and simplify
q = 117 . . . . . . . . . . . . . . . . . . multiply by 10
390-q = 273
The chef should use 273 mL of the first brand (5% vinegar) and 117 mL of the second brand (15% vinegar).
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<em>Additional comment</em>
You may have noticed that the value of q is (0.08 -0.05)/(0.10 -0.05)×390. The fraction of the mix that is the highest contributor is the ratio of the difference between the mix value and least contributor, divided by the difference between the contributors: (8-5)/(15-5) = 3/10, the fraction that is 15% vinegar. This is the generic solution to mixture problems.
The answer would be A. <span>The registration fee is $5.50, and the cost per download is $0.95.</span>
Solution
Let x = registration fee
y = cost/downloads
Jack
15y + x = 19.75 ; x = 19.75 - 15y
Jim
40y + x = 43.50
Thus,
40y + x = 43.50
40y + <span>19.75 - 15y = 43.50
</span>25y = 23.75
y= 0.95
for x,
<span>x = 19.75 - 15y</span>
x = 19.75 - 15( 0.95)
x= 19.75 -14.25
x = 5.5
32+33=65
60/2 is 30, so they have to be in their thirties. Then 2+3=5, therefore they must be 32 and 33
The distance formula between two points is d∧2=(x2-x1)∧2 + (y2-y1)∧2
The distance between Vista and Oceanside is
d1∧2=(-1-(-6))∧2+(6-2)∧2=(-1+6)∧2+4∧2=5∧2+16=25+16=41 => d=√41= 6.4
The distance between Oceanside and Alpena is
d2∧2=(0-(-1))∧2+(-1-6)∧2=1+(-7)∧2=1+49=50 => d2=√50=7.07
The distance between Vista and Alpena is
d3∧2=(0-(-6))∧2+(-1-2)∧2=36+9=45 => d3=√45= 6.7
Answer a) is Oceanside and Alpena
Answer b) is Vista and Oceanside
Good luck!!!
