4.78 is 4.776 to the nearest hundred
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Assuming the order required is as n-> inf.
As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.
We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).
So yes, both are o(log(n)).
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Answer: 30 is the least common multiple of 6 and 10.
Step-by-step explanation:
30/6= 5
30/10= 3.
Answer:
(See explanation for further details)
Step-by-step explanation:
The real expression is:
The general equation for the second-order polynomial is:
This condition must be observed for the case of a quadratic equation with equal roots:
