Triangles ABC and ADE are similar, meaning that
AB/BC=AD/DE
6/5=(6+x)/14
84/5=6+x
X=10.8
So x=10.8
We know that
in a right triangle
cos θ=adjacent side angle <span>θ/hypotenuse
in this problem
</span>adjacent side angle θ=38 in
hypotenuse=40 in
cos θ=38/40
θ=arc cos (38/40)-------> 18.19°-------> 18°
the answer is
18 degrees
24 units/C 48 units square units
Given: cos A = 5/13 = adj side / hypotenuse
The the opp side is given by (hypo)^2 = (adj)^2 + (opp)^2. Here,
13^2 = 5^2 + (opp)^2, so that
(opp)^2 = 169 - 25 - 144. Then opp = +12. All of these lengths are in Q I.
opp 12
Then sin A = -------- = -------- (answer)
hyp 13