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VladimirAG [237]

2 years ago

14

1. Attiana bought 5 packets of pumpkin seeds. Each packet contained 32 seeds. Attiana planted 1 packet of the seeds and 20 seeds

sprouted. Which statement about the seeds in the remaining packets is best supported by this data.

1 answer:

Verdich [7]2 years ago

4 0

Hehshsbshzujssvgsisksbegw

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Jerry is taking care of a vacant lot in his neighborhood. There are approximately 64 thistle weeds m the local

icang [17]

Answer:

16

Step-by-step explanation:

To be able to find the number of thistles that are in the vacant lot now using the information provided, you have to calculate the 75% of 64 and then, subtract that number from 64:

64*0.75=48

64-48=16

According to this, the answer is that there are 16 thistles in the vacant lot now.

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2 years ago

How you can know a fraction is equivalent to another fraction

Alex73 [517]

The denominator. Say for instance, you have 4/12 and 1/6. They are equivalent.

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3 years ago

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Maria bought 12.5 gallons of gasoline. There are approximately 3.8 liters in 1 gallon. Which measurement is closest to the numbe

allochka39001 [22]

Answer:

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Step-by-step explanation:

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2 years ago

Three hens can lay 3 eggs in 3 days. a In how many days can 7 hens lay 7 eggs?

Ann [662]

In 49 days they can lay 7 eggs

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2 years ago

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Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx

Soloha48 [4]

Answer:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

Step-by-step explanation:

For this case we need to find the following integral:

$\int x(8-x)^{3/2}dx$

And for this case we can use the substitution $u = 8-x$ from here we see that $du = -dx$ , and if we solve for x we got $x = 8-u$ , so then we can rewrite the integral like this:

$\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)$

And if we distribute the exponents we have this:

$\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du$

Now we can do the integrals one by one:

$\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C$

And reordering the terms we have"

$\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C$

And rewriting in terms of x we got:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

And that would be our final answer.

8 0

2 years ago