Calculate the work done by an applied force of 76.0 N on a crate for the following. (Include the sign of the value in your answe
1 answer:
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Answer:
W = 1.432 KJ
Explanation:
given,
mass = 22.2 Kg
angle of the rope = 27.5°
distance on the ground = 24 m
kinetic friction= μ = 0.32
acceleration due to gravity, g = 9.8 m/s²
Work done = ?
W = F d cosθ
a = 0 because it is moving with constant speed
equating all the forces acting in x direction
F cosθ = F friction = μN
equating all the forces acting in y direction
F sinθ + N -mg =0
now,
N = mg - F sinθ
putting value of N
F cosθ = μ mg -μ F sinθ
F (cosθ + μsinθ ) = μ mg
F =67.28 N
now,
W=F d cosθ
W =67.28 x 24 x cos(27.5)
W =1432.27 J
W = 1.432 KJ
Answer:
3.67 km
Explanation:
Joe distance towards coffee shop is,
And the Max distance towards bookstore is,
Now the distance between the Joy and Max will be,
By applying pythagorus theorem,
Substitute 0.40 km for OB and 3.65 km for OA in the above equation.
Therefore the distance between there destination is 3.67 km.
