The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as
molar mass=33.29g
<h3>What mass of
krypton tetrachloride can be
produced assuming 100% yield?</h3>
Generally, the equation for ideal gas is mathematically given as
PV=nRT
Therefore
n=(0.50)(15.)/0.082*623
n=0.147mol
Hence for clorine
n=0.441mol
Given the reaction
Kr+2cl2---->KrCL4
Hence
molar mass=225.60*0.147
molar mass=33.29g
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Answer is: [COCl₂] > [CO][Cl₂]
Chemical reaction: COCl₂(g) ⇄ CO(g) + Cl₂(g); Keq = 8.1 x 10⁻⁴.
Keq = [CO] · [Cl₂] / [COCl₂]; equilibrrium constant of chemical reaction.
[CO] · [Cl₂] / [COCl₂] = 0,00081.
Equilibrium product concentration is much more less than equilibrium concentration of reactant.
Answer:
i believe that the answer is D.
Explanation:
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