It’s to prove of the pounds and the congress to put each three out
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
The total length of rebar used is 21.66 meters.
Step-by-step explanation:
Given:
Ivan had cut a reinforcing bar in 19 pieces and length of each bar is 1.14 meters.
Number of pieces = 19
Length of each piece = 1.14
We need to find the total length of reinforcing bar.
To calculate the total length we will multiply number of pieces with length of each piece.
Hence,
Total length of rebar = Number of pieces × Length of each piece =
Rounding to nearest hundred = 21.66 m
Hence the total length of reinforcing bar is 21.66 meters.
Answer:
Step-by-step explanation:
25 because Becky read 45 and Jason read 20
45-20 = 25