At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange.
This is because that there are 6 orange desserts and n desserts altogether.
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange.
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts.
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1
The question lets us know that the shot of Hannah getting two orange desserts is 1/3.
So: 6/n x 5/n–1 = 1/3
Now, rearrange this problem.
(6x5)/n(n-1) = 1/3
This gets to be:
30/(n² – n) = 1/3
Times by 3 on both sides:
90/(n² – n) = 1
What's more, doing likewise with (n² – n):
So (n² – n) = 90
Our answer is: n² – n – 90 = 0
Answer:
15 Dollars
Step-by-step explanation:
If you take the shipping price (3 dollars) off you get 15 per shirt
W = 144. Evaluate the equations inside the parentheses. Which is 12 x 12 then evaluate that. Which equals, 144.
Answer:symptotes are invisible lines which are graphed function will approach very closely but not ever touch. This lesson covers vertical and horizontal
Step-by-step explanation: :)
This is an example of division. 252/6=42. So 42 toys will go into each pinata.
