Well ask yourself why don't we count it in moles and you should get your answer.
Answer:
The answer to your question is: 1538095.2 kg of NH3
Explanation:
MW HNO3 = 63 kg
MW NO2 = 46 kg
3 NO2(g) + H2O(l)--- 2 HNO3(aq) + NO(g)
3(46) kg-------------- 2(63) kg
x --------------- 7600000 kg
x = 7600000 x 138/126 = 8323809.5 kg og NO2
MW NO = 30
2 NO(g) + O2(g)---2 NO2(g)
2(30) ------------------2(46)
x ---------------- 8323809.5 kg
x = 8323809.5 x 60/92 = 5428571.4 kg of NO
MW NH3 = 17 kg
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)
4(17) -------------------- 4(30)
x ----------------------- 5428571.4
x = 5428571.4 x 34 / 120
x = 1538095.2 kg of NH3
Answer: Anna stated that ionic compounds have high melting point and low boiling point. The error in the statement is that ionic compound have low boiling point, instead ionic compounds have high boiling point, because in an ionic compound, the force of attraction working between two ions is very strong and hence the bonds present are very strong, and a lot of energy is needed to break them
<span>If the aqueous solution is 34% Licl then it is 100 - 34% water = 66%
From the calculation we've found out that it is 66% water. Then we need to find the weight from a 250 g solution.
66/100 * 250 = 165g
Hence it is 165g</span>
Answer:
Molecular weight of the compound = 372.13 g/mol
Explanation:
Depression in freezing point is related with molality of the solution as:
Where,
= Depression in freezing point
= Molal depression constant
m = Molality
m = 0.26
Molality = 
Mass of solvent (toluene) = 15.0 g = 0.015 kg
Moles of compound = 0.015 × 0.26 = 0.00389 mol
Mass of the compound = 1.450 g
Molecular weight = 
