Answer:
its B
Step-by-step explanation: just took test
Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
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x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
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<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
Answer:
18 pounds = 48 pizzas
18 pounds = 48 pizzas 22.5 pounds = 60 pizzas
18 pounds = 48 pizzas 22.5 pounds = 60 pizzas 27 pounds = 72 pizzas
Step-by-step explanation:
1) because they are ratios you multiply 18 and 8 (18 × 8 = 144) then you divide 144 by 3 (144÷3 =48)
2) now you do the same thing multiply 22.5 and 48 (22.5 × 48= 1,080) and divide 1,080 by 18 (1,080 ÷ 18= 60)
3) multiply 27 times 60 (27 × 60= 1,620) now divide 1,620 by 22.5 (1,620 ÷ 22.5= 72)
Answer:
Number of 1 $ bill = 20
Number of 5 $ bill = 6
Explanation:
Let p represent number of one dollar bolls and q represent number of five bills.
A total of 26 bills are in a cash box.
p + q = 26 ------------------------- Equation 1
The total amount of cash in the box is $50
p + 5q = 50 ------------------------- Equation 2
Equation 2 - Equation 1,
p + 5q - p -q = 50 - 26
4q = 24
q = 6
Substituting in equation 1.
p + 6 = 26
p = 20
Number of 1 $ bill = 20
Number of 5 $ bill = 6
Answer:
First write them in positive exponent form
(16/81)¾ × [ (9/25)^3/2 ÷ (2/5)³ ]
(2⁴×¾)/ (3⁴×¾) × [ (3² × ^3/2) / (5² ×^3/2) ÷ 2³/5³)
Simplify the terms
2³/3³ × ( 3³ / 5³ ÷ 2³/5³)
Solve the terms in the bracket
2³/3³ × (3³/5³×5³/2³)
You will get
2³/3³ × 3³/2³ = 1
They will cancel each other so the answer will be 1
Hope this helps.
