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2 years ago

Abby got a summer job. The table shows how much money she will earn based on the number of hours she works.

Mathematics

2 answers:

marishachu [46]2 years ago

5 0

Answer:

Step-by-step explanation:

She earns $487.50

375+75+37.5=487.5

Stels [109]2 years ago

3 0

Answer: c

Step-by-step explanation

First find the unit rate

$150 divided by 20 = $7.50

So she's earning $7.50 an hour

$7.50 times 65 hours = $487.50

So the correct answer is C

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Use cylindrical coordinates to evaluate the triple integral ∭ where E is the solid bounded by the circular paraboloid z = 9 - 16

4vir4ik [10]

Answer:

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

Step-by-step explanation:

The Cylindrical coordinates are:

x = rcosθ, y = rsinθ and z = z

From the question, on the xy-plane;

$9 -16 (x^2 + y^2) = 0 \\ \\ 16 (x^2 + y^2) = 9 \\ \\ x^2+y^2 = \dfrac{9}{16}$

$x^2+y^2 = (\dfrac{3}{4})^2$

where:

0 ≤ r ≤ $\dfrac{3}{4}$ and 0 ≤ θ ≤ 2π

∴

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} \int ^{9-16r^2}_{0} \ r \times rdzdrd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 z|^{z= 9-16r^2}_{z=0} \ \ \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 ( 9-16r^2}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} ( 9r^2-16r^4}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( \dfrac{9r^3}{3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3r^3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) d \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) \theta |^{2 \pi}_{0}$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{64}}-\dfrac{243}{320}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{160}})2 \pi$

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

4 0

2 years ago

It costs Danny $5 to park his car at a parking meter for 2 hours. What is the

Andre45 [30]

Answer:

$2.50

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

What are the surface area and volume of a regular triangular pyramid with a height of 9 cm and a slant height of 15 cm?

d1i1m1o1n [39]

I believe it is 135.
Hope this helps

3 0

3 years ago

True or false the values [x] and [-x] are always equal

RoseWind [281]

Answer:

If you mean |x| and |-x| yes they are equal.

Step-by-step explanation:

Brackets do not exactly specify the meaning of absolute value.

On most keyboards, above the enter button on the main keyboard part (not the keypad one) there is a back slash symbol \ and if you hold shift, there might be another symbol | which more accurately represents absolute value,

If you aren't talking about the absolute value, then no.

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2 years ago

How to find the area of a rectangular prism?

patriot [66]

(base area)*h
oibgrawjk gr/

8 0

2 years ago