Answer:
A(n)=130+13(n-1) ; 86
Step-by-step explanation:
Here is the sequence
130,143,156,169.......
the first term denoted by a is 130 and the common difference denoted by d is second term minus first term
143 - 130 = 13
Hence a=130 and d = 13
Now we have to evaluate to 13th term.
The formula for nth term of any Arithmetic Sequence is
A(n) = a+(n-1)d
Hence substituting the values of a ,and d get
A(n)=130+13(n-1)
To find the 13th term , put n = 13
A(13)=130+13*(13-1)
= 130+13*12
= 130+156
A(13) = 286
Answer:
Step-by-step explanation:
Well so it is asking you the statements and reasons and there is a select button it would be..... Hold on think about the letter formation. Just choose your best answer you think it is because if we are telling you thats cheating. But look above what I said. Think of the letter formation and quardinate with the question. I am speeding and yes I know I spelt it wrong.
Answer:
Therefore, the probability is P=3/32.
Step-by-step explanation:
We know that Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card.
We calculate the probability that he pulls out a 3 first and then pulls out a 2 without replacing them.
The probability that he pulls out a 3 first is 3/8.
The probability of a second card being 2 is 2/8.
We get:
Therefore, the probability is P=3/32.