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2 years ago

20 Points for 4 questions. BRAINLIEST also

Mathematics

1 answer:

pav-90 [236]2 years ago

8 0

Answer:

Image #1: -8 and 8

Image #2: -17 and -1

Image #3: 8 and 4

Image #4: -10±5√2

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Given: △ACE, BD∥AE<br><br> Prove: BA/CB=DE/CD<br><br> Drag

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

Angle 4 = angle 1 and angle 3 =angle 2 Corresponding angles for two parallel lines BD and AE

Triangle AED ||| BDE Angle angle congruent

... By compendo and dividendo

Thus proved

Since two lines are parallel we have corresponding angles equal and also

sides will be proportional in similar triangles

Using that and adjusting compendo and dividendo we get the desired result

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2 years ago

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Find the missing side of each triangle. Round your answers to the nearest tenth if necessary.

Aneli [31]

Answer:

9 miles

Step-by-step explanation:

use Pythagoras theorem

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2 years ago

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Is an imaginary "line" from the Earth to the Moon a line, a ray, or a segment? and WHY?

sesenic [268]

Answer:

Segment

Step-by-step explanation:

It is a segment because it has two endpoints (the Earth and Moon). If it was a ray, it would go on forever in one direction. It doesn't, so the imaginary line is a segment.

The first image is a segment, the second is a ray.

Hope this helps. :)

7 0

3 years ago

Determine whether The given segments have the same length. Justify your answer

Semenov [28]

We know the distance formula is

$\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }$

Here A( -4,2) and B(1,4)

So length of AB

= $\sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}$

Also C(2,1)

Length of BC

= $\sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}$

So we can see that length of AB is not equal to length of BC

11.

Now AB = $\sqrt{29}$

Also C(2,-1) & D(4,4)

Length of CD

= $\sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}$

Yes AB = CD

5 0

2 years ago

What’s the answer pls help me

defon

Answer:

H Maggie is write answers

8 0

2 years ago