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2 years ago

Please help me...? i'll give brainliest to correct answer! :D

Mathematics

2 answers:

elixir [45]2 years ago

8 0

Answer:

D) 100% Positve

Step-by-step explanation:

Sav [38]2 years ago

6 0

You would choose the second option (y=1/3x) because the slope would be 1/3. Think of the slope as your directions, you go up 1 over to the right 3 times. Since the y-intercept is 0, you don't have to add anything at the end.

Hope this answer makes sense.

You might be interested in

Find the distance between the points (5, -5) and (-7,4).

abruzzese [7]

Answer:

<h2>The answer is 15 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(5, -5) and (-7,4)

The distance between them is

$d = \sqrt{ ({5 + 7})^{2} + ({ - 5 - 4})^{2} } \\ = \sqrt{ {12}^{2} + ( { - 9})^{2} } \\ = \sqrt{144 + 81} \\ = \sqrt{225} \\ = 15 \: \: \: \: \: \:$

We have the final answer as

<h3>15 units</h3>

Hope this helps you

4 0

2 years ago

What other information do you need in order to prove the triangles

GuDViN [60]

Answer:

However, we need to know that segment AB is congruent to segment CD, in order to use SAS.

Hope it helps!

Step-by-step explanation:

7 0

2 years ago

Im lost im not sure what to do (Math Problem) plz Help!

Daniel [21]

Hello,

Answer C x²-7≠0 ==>(x≠-√7 and x≠√7)

8 0

2 years ago

#1 Identify the characteristics of the quadratic graph

shusha [124]

Vertex: (1,-3)
Y intercept: -3
Axis of symmetry x=1
Domain all real numbers
I only got these the rest I don’t know because I just started learning it but these are correct.

8 0

2 years ago

WILL GIVE BRAINLIEST

stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, $\text { distance travelled }=\text { speed } \times \text { time }$

For air force plane $\rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }$

$\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }$

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, $159 \times \text { time taken by air force plane }=207 \times 5.3$

$\Rightarrow =\frac{207 \times 5.3}{159}$

$\Rightarrow =\frac{1097.1}{159}$

Time taken by air force plane = 6.9 hrs

6 0

2 years ago