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Chemistry

2 answers:

lara31 [8.8K]2 years ago

7 0

Here is this picture with the answer I hope this helps !

erastovalidia [21]2 years ago

6 0

Proton
Location: nucleus
Charge: +1

Neutron
Location: nucleus
Charge: 0

Electron
Location: electron clouds(orbitals)
Charge: -1

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Substances that cannot be separated and found on a periodic table

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Substances that cannot be separated and found on a periodic table are elements.

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A group of students working in a high school chemistry lab believe they have discovered a new element! How exciting? Upon furthe

spayn [35]

Answer:

Explanation:

Information given about the element:

Number of protons = 74

Number of neutrons = 110

For the atomic number:

Neutral atoms such as this one would have their atomic number to be the same with their number of electrons and protons:

atomic number = number of protons = number of electrons

The atomic number would therefore be 74

For the mass number:

The mass of an atom is centrally concentrated within the tiny nucleus. The mass number is the sum of protons and neutrons in an atom. Protons and neutrons are nuclear particles and are called nucleons:

Mass number = number of protons + number of neutrons = 74+110=184

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From the peroidic table, tungsten(W) perfectly fits this description of the atom. It has an atomic number of 74 and a mass number of approximately 184. The element is not a new element.

Is it solid, liquid, or gas?

The element is a hard metallic solid. It is a classified as a transition metal on the periodic table. Transition metals have very unique metals and are mostly solids.

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If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

AVprozaik [17]

Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
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Find pOH
1 + pOH = 14

pOH = 13
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Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is $[OH-] = 1 * 10^{-13} mol/L$

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Answer:

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