Six times the sum of three consecutive odd integers is 18.Find the integers 1st integers (smallest of 3): 2nd integers (middle o
f 3): 3rd integers (largest of 3):
1 answer:
Answer:
-1, 1 and 3.
Step-by-step explanation:
Let the integers be n, n + 2 and n + 4, then
6( n + n+2 + n + 4) = 18
6(3n + 6) = 18 Divide through by 6:
3n + 6 = 3
3n = -3
n = -1
So the integers are -1, 1 and 3.
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