It’s hard to perfectly measure the distance something travels, as well as the exact time it takes, making the results have some variation.
Answer: 2.7 m/s
Explanation:
Given the following :
Period (T) = 8.2 seconds
Radius = 3.5 m
The tangential speed is given as:
V = Radius × ω
ω = angular speed = (2 × pi) / T
ω = (2 × 22/7) / 8.2
ω = 6.2857142 / 8.2
ω = 0.7665505
Therefore, tangential speed (V) equals;
r × ω
3.5 × 0.7665505 = 2.6829268 m/s
2.7 m/s
Answer:
The momentum is 1.94 kg m/s.
Explanation:
To solve this problem we equate the potential energy of the spring with the kinetic energy of the ball.
The potential energy of the compressed spring is given by
,
where is the length of compression and is the spring constant.
And the kinetic energy of the ball is
When the spring is released all of the potential energy of the spring goes into the kinetic energy of the ball; therefore,
solving for we get:
And since momentum of the ball is ,
Putting in numbers we get:
Answer:
F = −10093.41 N
Explanation:
Given that,
Mass of a baseball, m = 143 g = 0.143 kg
Initial speed of the baseball, u = +38.8 m/s
The hitter's bat is in contact with the ball for 1.20 ms and then travels straight back to the pitcher's mound at a speed of 45.9 m/s, v = -45.9 m/s
We need to find the average force exerted on the ball by the bat. So, Force is given by :
a is acceleration
So, the average force exerted on the ball by the bat has a magnitude of 10093.41 N.