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1 year ago

PLEASE HELP 15 POINTS AND BRAINIEST!!! Reporting fake answers

Physics

1 answer:

Leviafan [203]1 year ago

6 0

The period, speed and acceleration of a satellite are only dependent upon the radius of orbit and the mass of the central body that the satellite is orbiting. I hope this helps. Sorry if i am wrong.

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The time period T of a simple pendulum is given by the relation

Vanyuwa [196]

Answer:

$T^2 \propto L$

Explanation:

The period of a simple pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration of gravity

From this equation we can write

$T\propto \sqrt{L}\\T\propto \frac{1}{\sqrt{g}}$

Taking the square of this equation, we get:

$T^2 = (2\pi)^2 \frac{L}{g}$

So we see that $T^2$ is proportional to L and inversely proportional to g. So, we can write:

$T^2 \propto L\\T^2 \propto \frac{1}{g}$

So the only correct option is

$T^2 \propto L$

5 0

2 years ago

Read 2 more answers

What does mind-body-spirit connection mean to you?

Leno4ka [110]

Answer:

like I see it as how well you're connected with yourself

5 0

1 year ago

A rocket, blasting into space, accelerates at 2 m/s^2 for 20 seconds. What is its speed at the end of 20 seconds?

OLEGan [10]

Answer:

Acceleration = (change in speed) / (time for the change)

Change in speed = (ending speed) - (beginning speed)

= (3,600 mi/hr) - ( 0 )

= 3,600 mi/hr

= same as 1 mile/second.

Acceleration = (1 mi/sec) / (10 sec)

= 0.1 mi/sec² .

But 1 mile = 5,280 ft,

0.1 mi/s² = 528 ft/s²

Explanation:

have a great day

4 0

2 years ago

Two trains travel at right angles to each other after leaving the same train station at the same time. Two hours later they are

Vikentia [17]

Answer:

Speed of faster train equals 29 mph

Explanation:

Let the speed of slower train be 'x' miles per hour and the speed of faster train be 'y' miles per hour.

Distance that slower train covers in 2 hours= $2\times x miles$

Distance that faster train covers in 2 hours= $2\times y miles$

Since they move at right angles the distance between them can be found by Pythagoras formula as

$d^{2}=(2x)^{2}+(2y)^{2}\\\\d^{2}=4(x^{2}+y^{2})\\(70.46)^{2}=4(x^{2}+y^{2})\\\\\therefore (x^{2}+y^{2})=\frac{(70.46)^{2}}{4}\\\\(x^{2}+y^{2})=\frac{4964.6}{4}\\\\(x^{2}+y^{2})=1241.15$

It is given that $y=x+9$

Using this in the above equation we get

$(x^{2}+y^{2})=1241.15\\\\x^{2}+(x+8)^{2}=1241.15\\2x^{2}+16x+64=1241.15\\2x^{2}+16x-1177.15=0$

This is a quadratic equation in 'x'

Comparing with standard quadratic equation $ax^{2}+bx+c$ we get value of x as

$(x^{2}+y^{2})=1241.15\\\\x^{2}+(x+8)^{2}=1241.15\\2x^{2}+16x+64=1241.15\\2x^{2}+16x-1177.15=0\\\\x=\frac{-16\pm \sqrt{(16)^{2}-4\times 2\times -1177.15}}{2\times 2}\\\\x=\frac{-16\pm 98.35}{4}\\\\x=20.58mph(\because speed\neq$

Thus speed of faster train = 28.58 mph

Speed of faster train = 19 mph

3 0

3 years ago

Read 2 more answers

The electric current leaves the battery passes through the it then travels through the next through the and finally padses throu

miss Akunina [59]

<span>The answers are:

bulb, motor, buzzer and swtich.

As seen in the picture attached,

The electric current leaves the battery passes through the bulb. It then travels through the motor, next through the buzzer and finally passes through the switch before returning to the battery.</span>

8 0

2 years ago