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2 years ago

Add or subtract write your Answer in simplest form

Mathematics

1 answer:

Brums [2.3K]2 years ago

5 0

Answer:

The answer is 1 and 1/4

The second option

Step-by-step explanation:

Hopes this helps

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After transforming f(x) = 2x² + 4x + 3 into vertex form, the vertex is easily identifiable. Which ordered pair is the vertex?

vagabundo [1.1K]

Answer:

The correct answer to your question is A because your asking for the vertex of the equation.

Step-by-step explanation:

Vertex Algebraic Equations

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2 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree)

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2 years ago

Please help and show work!!

serious [3.7K]

17.

x = -2 is not a solution of -1 < x < 5 because -2 < -1 (-1 < -2 < 5 FALSE).

18.

m = 5 is a solution of 5 ≤ m because 5 ≤ 5 ( 5 ≤ m → m ≥ 5 greater than 5 or equal 5, 5 is equal 5)

19.

k = 10 is not solution of 2k - 3 < 1 because:

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2(10) - 3 < 1

20 - 3 < 1

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2 years ago

Solving Quadratic Equations using the Square Root Property

Afina-wow [57]

Answer:

$x = -2$ or $x = -5$

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

$x^2 + 7x + 10 = 0$

Subtract 10 from both sides.

$x^2 + 7x = -10$

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

$x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = \dfrac{9}{4}$

Now we use the square root property, if

$x^2 = k$ , then

$x = \pm \sqrt{k}$

$x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}$

$x + \dfrac{7}{2} = \pm \dfrac{3}{2}$

$x + \dfrac{7}{2} = \dfrac{3}{2}$ or $x + \dfrac{7}{2} = -\dfrac{3}{2}$

$x = -\dfrac{4}{2}$ or $x = -\dfrac{10}{2}$

$x = -2$ or $x = -5$

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2 years ago

Which transformation is not isometric?

kumpel [21]

D .............................

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2 years ago

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