Answer:
D) 1.61 times faster
Explanation:
= √(3)RTM
R constant= 0.08206
T=constant, so in this problem we dont need a value for it
M=17.031 g/mol
√(3)(0.08206)(17.031)= 2.047
= √(3)RTM
R constant= 0.08206
T=constant, so in this problem we dont need a value for it
M= 44.01 g/mol
√(3)(0.08206)(44.01)= 3.29
Since we are trying to measure how much faster NH3 will be, we have to realize that mass and speed have an inverse relationship.
So instead of doing (2.047)/(3.29) = 6.22
we have to flip the values to get (3.29)/(2.047)= 1.61
Answer:
0.075 moles of product formed.
Explanation:
Given data:
Number of moles of oxygen = 0.30 mol
Number of moles of oxygen = 0.15 mol
Number of moles of product formed = ?
Solution:
Chemical equation:
4Na + O₂ → 2Na₂O
Now we will compare the moles of Na₂O with oxygen and sodium.
Na : Na₂O
4 : 2
0.15 : 2/4×0.15 = 0.075 mol
O₂ : Na₂O
1 : 2
0.30 : 2/1×0.30 = 0.6 mol
Less number of moles of Na₂O are produced by sodium thus it will limit the yield of Na₂O and act as limiting reactant while oxygen is in excess.