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2 years ago

HELP ASAP!!!!! ILL MARK YOU BRAINLIEST!

2 answers:

8 0

Hello! Sorry this is a little late!

The answer to your question would best be option C, y<span>es, because electric charges have electric fields surrounding them that allow them to exert forces on other objects without touching them.

I just took this test, and can 100% confirm this is the correct answer!

Hope this helps, and have a great day! :)</span>

valkas [14]2 years ago

3 0

Answer:

c. Yes, because electric charges have electric fields surrounding them that allow them to exert forces on other objects without touching them.

Explanation:

As we know by Coulomb's law the force of attraction or force of repulsion between two charged bodies is given by

$F = \frac{kQ_1Q_2}{r^2}$

now we know that

if two charges are of same sign then they will repel each other and if the two charges are of opposite sign then they must attract each other.

So here since two balloons are of negative charge so we can say that electric field on one balloon will repel the charge of other balloon.

So here both balloons will repel each other and correct answer will be

c. Yes, because electric charges have electric fields surrounding them that allow them to exert forces on other objects without touching them.

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A chinook salmon needs to jump a waterfall that is 1.5 m high. If the fish starts from a distance of 1.00 m from the base of the

____ [38]

<span>let the fsh jump with initial velocity (u) in direction (angle p) with horizontal

it can cross and reach top of trajectory if its top height h = 1.5m
and horizontal distance d = (1/2) Range
--------------------------------------...
let t be top height time
at top height, vertical component of its velocity =0
vy = 0 = u sin p - gt
t = u sin p/g
h = [u sin p]*t - 0.5 g[t[^2
1.5 = u^2 sin^2 p/g - u^2 sin^2 p/2g
u^2 sin^2 p/2g = 1.5
u^2 sin^2 p = 1.5*2*9.8 = 29.4
u sin p = 5.42 m/s >>>>>>>>>>>>>>> V-component
=====================
t = HALF the time of flight
d = (1/2) Range (R) = (1/2) [2 u^2 sin p cos p/g]
1 = u^2 sin p cos p/g
u sin p * u cos p = 9.8
5.42 * u cos p = 9.8
u cos p = 1.81 m/s >>>>>>>>>>>>> H-component
check>>
u = sqrt[u^2 cos^2 p + u^2 sin^2 p] = 5.71 m/s
u < less than fish's potential jump speed 6.26 m/s

so it will able to cross</span>

8 0

2 years ago

During heavy rain, a section of a mountainside measuring 2.5 km horizontally, 0.80 km up along the slope, and 2.0 m deep slips i

Crank

Answer:

The mass of the mud is 3040000 kg.

Explanation:

Given that,

length = 2.5 km

Width = 0.80 km

Height = 2.0 m

Length of valley = 0.40 km

Width of valley = 0.40 km

Density = 1900 Kg/m³

Area = 4.0 m²

We need to calculate the mass of the mud

Using formula of density

$\rho=\dfrac{m}{V}$

$m=\rho\times V$

Where, V = volume of mud

$\rho$ = density of mud

Put the value into the formula

$m=1900\times4.0\times0.40\times10^{3}$

$m =3040000\ kg$

Hence, The mass of the mud is 3040000 kg.

4 0

2 years ago

Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley

kenny6666 [7]

Answer:

Hello your question is incomplete attached below is the complete question

Answer : x ( acceleration of mass 4m ) = $\frac{g}{7}$

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

Explanation:

Given data:

mass suspended = 4 meters

mass suspended at other end = 3 meters

first we have to express the kinetic and potential energy equations

The general kinetic energy of the system can be written as

T = $\frac{4m}{2} x^2 + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2$

T = $4mx^2 + 2my^2 -2mxy$

also the general potential energy can be expressed as

U = $-4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant$

The Lagrangian of the problem can now be setup as

$L =4mx^2 +2my^2 -2mxy +2mgy + constant$

next we will take the Euler-Lagrange equation for the generalized equations :

Euler-Lagrange equation = $4x-y =0\\-2y+x +g = 0$

solving the equations simultaneously

x ( acceleration of mass 4m ) = $\frac{g}{7}$

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

8 0

2 years ago

If a car increases its velocity from zero to 60 m/s in 10 seconds, its acceleration is

andrezito [222]

We know that a=vf_vi/t equals equation "a" . Where a is the acceleration of the body , vf is the final velocity , vi is the initial velocity and t is equal to time . Since vi equals o m/s , vf equals to 60 m/s and t equals 10 s. Put in equation "a". a=60-0/10 =6m/s2

5 0

2 years ago

If a car stopped then accelerates at 25m/s2 for 2 seconds what is the final velocity of the car?

nalin [4]

The velcocity equals acceleration times time
which is 50 ms per sec

5 0

3 years ago

HELP ASAP﻿﻿!!!!! ﻿ILL MARK YOU BRAINLIEST!

HELP ASAP!!!!! ILL MARK YOU BRAINLIEST!