Answer:
a)M=0.20/(0.335*0.1025)= 0.20/ 0.034 = 5.88 g/mol
b) if 0.100g is used instead of 0.200g
M = 0.1 / 0.034 = 2.94 hence the molar mass will be too low
Explanation:
0.2000 gHZ gives 100ml acid solution
33.5 ml of 0.1025 M NaOH is required to prepare it
the moles = mass / molar mass
mass = 0.200 gHZ
moles = 0.0335*100 * 0.1025 = 0.034
therefore molar mass = mass / moles
M=0.20/(0.335*0.1025)= 0.20/ 0.034 = 5.88
if 0.100g is used instead of 0.200g
M = 0.1 / 0.034 = 2.94 hence the molar mass will be too low
Answer:
NO3 that is the answer to the question
Answer:
A) (3.2g)
Explanation:
Did you reposed this? Because I remember answering this