No, the sum of the lengths of any two sides must be greater than the length of the third side
Answer:
see explanation
Step-by-step explanation:
The common difference d of an arithmetic sequence is
d = - = -
Substitute in values and solve for k, that is
5k - 1 - 2k = 6k + 2 - (5k - 1)
3k - 1 = 6k + 2 - 5k + 1
3k - 1 = k + 3 ( subtract k from both sides )
2k - 1 = 3 ( add 1 to both sides )
2k = 4 ⇒ k = 2
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The n th term of an arithmetic sequence is
= + (n - 1)d
= 2k = 2 × 2 = 4 and
d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5
Hence
= 4 + (7 × 5) = 4 + 35 = 39
Answer:
The numerical length of RS is 22 units
Step-by-step explanation:
∵ Point S is on the line segment RT
→ <em>That means S divide RT into two parts RS and ST</em>
∴ RS + ST = RT
∵ RS = 4x - 10
∵ ST = 2x - 10
∵ RT = 4x - 4
→ <em>Substitute them in the statement above</em>
∴ 4x - 10 + 2x - 10 = 4x - 4
→ <em>Add the like terms in the left side</em>
∴ (4x + 2x) + (-10 + -10) = 4x - 4
∴ 6x + (-20) = 4x - 4
∴ 6x - 20 = 4x - 4
→ <em>Add 20 to both sides</em>
∴ 6x -20 + 20 = 4x - 4 + 20
∴ 6x = 4x + 16
→ <em>Subtract 4x from both sides</em>
∴ 6x - 4x = 4x - 4x + 16
∴ 2x = 16
→ <em>Divide both sides by 2 to find x</em>
∴
∴ x = 8
→ <em>Substitute the value of x in Rs to find its length</em>
∵ RS = 4(8) - 10
∴ RS = 32 - 10
∴ RS = 22 units
The numerical length of RS is 22 units
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