Given: triangle ABC and triangle EDC, C is the midpoint of BD and AE. Prove: AB || DE
1 answer:
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Answer:
see explanation
Step-by-step explanation:
I don't have graphing facilities but can give you the vertex and 1 other point.
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = -
y = - x² - 2x + 8 ← is in standard form
with a = - 1 and b = - 2 , then
x = - = - 1
Substitute x = - 1 into the equation for corresponding value of y
y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9
vertex = (- 1, 9 )
To obtain another point substitute any value for x into the equation
x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph
x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0 then (2, 0 ) is a point on the graph
See in the explanation
<h2>Explanation:</h2>In this exercise, <em>we have the following points:</em>
And <em>the following linear equations:</em>
When plotting these graphs, we find the following facts:
<h3>For (1):</h3>We see the graph in the first figure below. The graph only passes through the point (0, 8)
<h3>For (2):</h3>This is the second graph below. The graph passes neither through point (0, 8) nor (6, 4)
<h3>For (3):</h3>This is the third graph below. The graph passes neither through point (0, 8) nor (6, 4)
<h3>For (4):</h3>This is the fourth graph below. The graph only passes through the point (0, 8)
So, <em>there is no any equation of the line that passes through the points (0.8) and (6.4) at the same time.</em>
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<h2>Learn more:</h2>About lines: brainly.com/question/12169569
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