I'll leave the computation via R to you. The are distributed uniformly on the intervals , so that
each with mean/expectation
and variance
We have
so that
Now,
and
We have
because and are independent when , and so
giving a variance of
and so the standard deviation is
# # #
A faster way, assuming you know the variance of a linear combination of independent random variables, is to compute
and since the are independent, each covariance is 0. Then
and take the square root to get the standard deviation.
Given :
▪︎This triangle is an isosceles triangle.
▪︎Measure of one of its legs = 6 inches
▪︎Measure of its equivalent leg inches
▪︎Measure of its base inches
Which means :
Let us check whether or not we have found out the correct value of x by placing 54 in the place of x :
Since the Left Hand Side of the equation is equivalent to the Right Hand Side of the equation, we can conclude that we have found out the correct value of x.
▪︎Therefore, the value of <u>x = 54</u>
The total cost for the entire life span of the deep fryer is computed below:
Brand P total cost =Purchase price + total electricity cost
= $144+($0.49x8x12x6)
=$426.24
Brand Q total cost =(Purchase price x 3)+ total electricity cost
=( $37.5x3)+($0.75x 8x12x6)
= $544.5
Difference = Brand Q-Brand P
=$544.5-$426.24
=$118.26
Robert will have to choose Brand P because it will be cheaper by $118.26 than Brand Q in their entire lifetime.
Answer:
88.88% probability that it endures for less than a year and a half
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The next career begins on Monday; what is the likelihood that it endures for less than a year and a half?
One year has 52.14 weeks. So a year and a half has 1.5*52.14 = 78.21 weeks.
So this probability is the pvalue of Z when X = 78.21.
has a pvalue of 0.8888
88.88% probability that it endures for less than a year and a half