For ADC you just add those two numbers. your answer would be D) 131
Answer:
1. 7x
2. 8x - 1
3. 6x + 12
4. 3x + 4
5. 13x - 7
Step-by-Step Explanation:
Hope this helps!
Deijah has $6.25.
Now, this 6.25 is comprised of 0.05s and 0.25s.
We know that there are 12 0.25s.
We now want to know how many remaining 0.05s there are.
Again, we know that the number of 0.05s he has, which is 12, multiplied by 0.05, plus the number of 0.25s he has, multiplied by 0.25, equals 6.25.
Thus, the answer is A, 0.25 x 12 + 0.05 x n = 6.25.
Answer:
There are N students in the class.
We know that ONLY ONE of the inequalities is true:
N < 10
N > 10
N < 22
N > 22
We want only one of these four inequalities to be true.
Remember that if we have:
x > y
y is not a solution, because:
y > y is false.
Then:
If we take N = 10, then:
N < 22
Is the only true option.
While if we take N = 22
N > 10
is the only true option.
So there are two possible values of N.
D͓̽o͓̽m͓̽a͓̽i͓̽n͓̽: {-6 ≥x͓̽≤ 5}
R͓̽a͓̽n͓̽g͓̽e͓̽: {-1 ≥y͓̽≤ 4}