Please help I’ve been trying to get answers for days now :/

Mathematics

1 answer:

kirza4 [7]2 years ago

3 0

Answer:

If the whole box is the sports store then its just 80m if its just the equipment section then its 56m

Step-by-step explanation:

8x10=80

80-(6x4)=56 80-24=56

You might be interested in

PLEAS HELP

myrzilka [38]

2312 FPM for 2.6 minutes

2312 x 2.6 = 6011.2

28 FPM for 2 minutes

28 x 2 = 56

6011.2 descend

55 ascend

0-6011.2 = -6011.2

ans + 56 = -5955.2

5 0

1 year ago

A person can pay $14 for a membership to the history museum and then go to the museum for just $5 per visit. What is the maximum

umka2103 [35]

Hi there!
First we subtract 44-14 leaving us with 30. 5x6 = 30
Therefore, a member can visit a history museum 6 times to equal a total cost of $44.
In a different situation:
If the person has already paid the $14, and that doesn’t count as a visit, then a person would have to visit a museum 8 times to get a total of $45. Considering this is a real-world problem.
I hope this helps and have a good day :) !
~Angel

8 0

3 years ago

A bag contains seven tiles labeled B, C, D, E, F, G, and H. One tile will be randomly picked. What is the probability of picking

Licemer1 [7]

Answer:

$\sf \dfrac{1}{7}$

Step-by-step explanation:

Given labeled tiles: B, C, D, E, F, G, H

Total number of tiles = 7

Vowels = A, E, I, O and U

⇒ Total number of vowel tiles in bag = 1

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

$\implies \sf Probability\:of\:picking\:a\:vowel= \dfrac{Number\:of\:vowel\:tiles}{Total\:number\:of\:tiles}=\dfrac{1}{7}$

7 0

2 years ago

Kali invests $3516 in a savings account with a fixed annual interest rate of 7% compounded 3 times per year. What will the accou

ZanzabumX [31]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3516\\
r=rate\to 7\%\to \frac{7}{100}\to &0.07\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{well, is just three}
\end{array}\to &3\\
t=years\to &7
\end{cases}
\\\\\\
A=3516\left(1+\frac{0.07}{3}\right)^{3\cdot 7}\implies A=3516\left( \frac{307}{300} \right)^{21}\implies A\approx 5707.0070$