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2 years ago

Please tell me answer not by directly step by step please don't write answer only please please please

Mathematics

2 answers:

bixtya [17]2 years ago

8 0

y + z + r + x = 360

2x + 3x + 4x + x = 360

10x = 360

x = 360/10

x = 36

Now

x = 36

y = 72

z = 108

r = 144

Answered by Gauthmath must click thanks and mark brainliest

irinina [24]2 years ago

7 0

Step-by-step explanation:

Given,

y=2x=,z=3x,r=4x

Now,

x+y+z+r=360°(complete turn)

x+2x+3x+4x=360°(given)

10x=360°

x=360°/10

x=36°

Hence,

x=36°

y=2x=2×36°=72°

z=3x=3×36°=108°

r=4x=4×36°=144°

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2 years ago

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The hypotenuse of a 30o-60o-90o triangle measures 4 square 3 inches. What is the length of the shorter leg?

Fofino [41]

Answer:

The shorter leg is $2\sqrt{3}$ inches

Explanation:

The 30°-60°-90° is a special type of right-angled triangles

It has the following special side length:

The length of the side opposite to the 30° is $\frac{1}{2}$ the length of the hypotenuse

The length of the side opposite to the 60° is $\frac{\sqrt{3} }{2}$ of the hypotenuse

Now, we know that the lengths of the sides in a triangle are proportional to the angles

This means that the shortest side will be the one opposite to the smallest angles

In our case, the shortest side will be the one opposite to the 30° angle

We are given that the hypotenuse of the triangle is $4\sqrt{3}$ in

From the above:

Shorter leg = leg opposite to 30° = $\frac{1}{2} * hypotenuse = \frac{1}{2} * 4\sqrt{3} = 2\sqrt{2}$ inches

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2 years ago

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mr Goodwill [35]

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2 years ago

If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

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2 years ago