Answer:
The mean of the distribution of heights of students at a local school is 63 inches and the standard deviation is 4 inches.
Step-by-step explanation:
The normal curve approximating the distribution of the heights of 1000 students at a local school is shown below.
For a normal curve, the mean, median and mode are the same and represents the center of the distribution.
The center of the normal curve below is at the height 63 inches.
Thus, the mean of the distribution of heights of students at a local school is 63 inches.
The standard deviation represents the spread or dispersion of the data.
From the normal curve it can be seen that values are equally distributed, i.e. the difference between two values is of 4 inches.
So, the standard deviation is 4 inches.
Step-by-step explanation:
P(heads) = ½, and P(tails) = ½
a) P(5 heads) = (½)⁵ = ¹/₃₂
b) P(5 tails) = (½)⁵ = ¹/₃₂
c) P(at least 1 head) = 1 − P(all tails) = ³¹/₃₂
Answer:
-32
Step-by-step explanation:
Simply input the x and y values.
New equation:
| 147-(-9) | /(-4) +7
Step one:
<em>147-(-9) = 156</em>
<em>Step two:</em>
|156|/-4 =-39
Step three:
-39+7 =-32
If you evaluate the expression it comes out to -32
Answer:
44, 21
Step-by-step explanation:
x+y = 2x-23
x-y = 2y - 19
Rewrite
-x + y = -23
x - 3y = -19
Use elimination.
1: 4.5 ft by 6 ft
2: 27 sq. ft.
First, just multiply 3 and 4 by 1.5 to convert inches to feet using the scale. You end up with 3*1.5 and 4*1.5, which equals 4.5 and 6. So the dimensions are 4.5 feet by 6 feet.
Now, just multiply 4.5 by 6 to get 27 square feet.
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