Quadratic equations w complex roots x2 - 6x + 12 = 0
1 answer:
Answer:
x = 3 ± i
Step-by-step explanation:
Given
x² - 6x + 12 = 0 ( subtract 12 from both sides )
x² - 6x = - 12
Using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 3)x + 9 = - 12 + 9
(x - 3)² = - 3 ( take the square root of both sides )
x - 3 = ± = ± i
( add 3 to both sides )
x = 3 ± i
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