Answer:
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
Step-by-step explanation:
Given:
Length of drive way at garage door = 12 feet
Length of drive way at street = 20 feet
Length of total driveway = 18 feet
Find:
Amount of Winter sealer for 2 coats[in square feet]
Computation:
Amount of Winter sealer for 2 coats[in square feet] = 2[Area of trapezoid]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(Sum of parallel side)(Height)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(12 + 20)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(32)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 32 x 18
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
Answer:
1/5 divided by 4 equals to 0.05
The width of the rectangle is 6.82 meters, while the length of the rectangle is 8.184 meters.
<h3>What is a rectangle?</h3>
A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. A rectangle is always a parallelogram and a quadrilateral but the reverse statement may or may not be true.
Let the width of the rectangle be x.
Given that a rectangular room is 1.2 times as long as it is wide. Therefore, the length is 1.2x.
Perimeter = 2(x + 1.2x)
30 meters = 2(2.2x)
30 = 4.4x
x = 6.82
Hence, the width of the rectangle is 6.82 meters, while the length of the rectangle is 8.184 meters.
Learn more about Rectangle:
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To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.
Prime factorization of 36=2×2×3×3
Prime factorization of 40=2×2×2×5
Prime factorization of 48=2×2×2×2×3
Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.
720seconds=
60
720
minutes=12minutes
Hence, all the bells will ring together after 12 mi
5 digit number with no repeats
1st digit has 9 possibilities
2nd digit has 8 possibilities
3rd digit has 7 possibilities
4th digit has 6 possibilities
5th fight has 5 possibilities
Therefore the answer is:
9 x 8 x 7 x 6 x 5 = 72 x 210 = 15,120
