Ask question

Ask question

All categories

2 years ago

6

The reputation of a city has been decreasing exponentially since 1990. In 1990, the population was 1,000,000. In 2010, the popul

ation was 560,000. If t represents time in years since 1990, which of the following equations
best models the decay of the population?

1 answer:

ad-work [718]2 years ago

8 0

Answer:

i think you have to soleve that srry

You might be interested in

Write the measure 29° 6' 6" as decimal to the nearest thousandth.

den301095 [7]

This angle is "29 degrees 6 minutes 6 seconds".

-- There are 60 minutes in 1 degree.
   So 1 minute = 1/60 degree.

-- There are 60 seconds in 1 minute.
      So 1 second = 1/60 minute = 1/3600 degree.

29 6' 6" = (29)° + (6/60)° + (6/3600)°

   = (29)° + (0.1)° + (0.001666...)°

   = 29.101666...°

Rounded to the nearest thousandth of a degree: 29.102°

6 0

2 years ago

21000.7895÷444477777

Radda [10]

<span>21000.7895÷444477777</span>= 0.00004724823

4 0

2 years ago

P(x)= 3x^3-5x^2-14x-4

nexus9112 [7]

$\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\
$

$\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)$

$\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm \sqrt{4+16}}{2}=\frac{2\pm \sqrt{20}}{2}=\frac{2\pm 2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}$

7 0

2 years ago

A 60 <br> B 30 <br> C 1 20<br> D 15<br> fastest answer gets brainiest

Anuta_ua [19.1K]

Answer:

i think it would be A

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Is 3.4 a real number

anzhelika [568]

Answer: Yes, it is a real number. 3.4 is a rational number and rational numbers are real numbers. So 3.4 is a real number.

3 0

2 years ago