Answer:
P = 2439.5 W = 2.439 KW
Explanation:
First, we will find the mass of the water:
Mass = (Density)(Volume)
Mass = m = (1 kg/L)(10 L)
m = 10 kg
Now, we will find the energy required to heat the water between given temperature limits:
E = mCΔT
where,
E = energy = ?
C = specific heat capacity of water = 4182 J/kg.°C
ΔT = change in temperature = 95°C - 25°C = 70°C
Therefore,
E = (10 kg)(4182 J/kg.°C)(70°C)
E = 2.927 x 10⁶ J
Now, the power required will be:
where,
t = time = (20 min)(60 s/1 min) = 1200 s
Therefore,
<u>P = 2439.5 W = 2.439 KW</u>
The distance between Mars and the Sun in the scale model would be 1140 m
Explanation:
In this scale model, we have:
represents an actual distance of
The actual distance between Mars and the Sun is 228 million km, therefore
On the scale model, this would corresponds to a distance of 
.
Therefore, we can write the following proportion:
And solving for , we find:
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Motion Energy
I am writing this so it can be more than 20 letters
E) Protons, neutrons, and electrons
Answer:
C). 
Explanation:
As we know that capacitance of a given capacitor is
now we know that energy stored in the capacitor plates
here if all the dimensions of the capacitor plate is doubled
then in that case
here area becomes 4 times on doubling the radius and the distance between the plates also doubles
So new capacitance is now
so capacitance is doubled
now the final energy stored between the plates of capacitor is given as
so the final energy is
