<span>The formation of a derivative being a necessary step in the experiment lies in the importance of the derived structure. Often the derived product confers to reaction pathways which uses less reactive starting materials and more easily proceeds to completion. This also allows us to take a small amount of sample. The derived product at times is a general compound allowing its easy analysis. Often we encounter a product but we find it difficult to analyse it in ways we want. Here lies the essence of forming a derivative which often are simpler compounds allowing easier analysis yet having similar functional groups and structural properties. Also sometimes we encounter problems when our desired product is unstable and forms stable degraded products. But if we somehow manage to synthesize a derivative it may be relatively stable and form no degradation products. It would be stable at least for a significant period of time making it easier to study its properties. The derived product also at times are synthesized using general reaction pathways facilitating a way of easier synthesis and helping it to correlate with other similar reaction pathways and products.So the above paragraph accounts for the need of derivatives. When we encounter problems similar to those mentioned above it becomes necessary for a researcher to form rather synthesize a derivative.</span>
It is 100 because a 5 and up means you round up. also the 9 makes it a 6 rounded up
Answer:
The mass number tells us the number (the sum of nucleons) of protons and neutrons in the nucleus of an atom. The atomic number (also known as the proton number) is the number of protons found in the nucleus of an atom. It is traditionally represented by the symbol z
Explanation:
Answer: melting points are major means of identifying pure compounds.
Explanation:
A pure compound can be identified by its melting point because, a pure compound will have a sharp melting point while an impure compound will melt over a temperature range. If presented with a pure sample of an unknown solid, its melting point can tell us what the identity of the compound. Similarly, melting point analysis can show the purity of a known solid. If the known solid has a sharp melting point, then it is pure.
Hey there!
First we need to find the molar mass of Ca(OH)₂.
Ca: 1 x 40.078
O: 2 x 16
H: 2 x 1.008
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74.094 grams
Find how many moles are in 523 grams of Ca(OH)₂.
523 ÷ 74.094 = 7.06 moles
There are 2 atoms of oxygen in each molecule of Ca(OH)₂.
7.06 x 2 = 14.12
523g of Ca(OH)₂ contains 14.12 moles of oxygen.
Hope this helps!
