Answer:
it will take 36.12 ms to reduce the capacitor's charge to 10 μC
Explanation:
Qi= C×V
then:
Vi = Q/C = 30μ/20μ = 1.5 volts
and:
Vf = Q/C = 10μ/20μ = 0.5 volts
then:
v = v₀e^(–t/τ)
v₀ is the initial voltage on the cap
v is the voltage after time t
R is resistance in ohms,
C is capacitance in farads
t is time in seconds
RC = τ = time constant
τ = 20µ x 1.5k = 30 ms
v = v₀e^(t/τ)
0.5 = 1.5e^(t/30ms)
e^(t/30ms) = 10/3
t/30ms = 1.20397
t = (30ms)(1.20397) = 36.12 ms
Therefore, it will take 36.12 ms to reduce the capacitor's charge to 10 μC.
I was struck by this many years ago while in graduate school. ... People with mental illness tend to die young , but so do their families. ... there is no medical assessment that can diagnose the absence of illness.
Answer:Frequency = 3.525 Hertz
Explanation:In static equilibrium, kd =mg
Where k= effective spring constant of the spring.
mg= The weight of the car.
d= static deflection.
Therefore, w =SQRTg/d
w = SQRT 9.81/0.02
w= 22.15 rad/sec
Converting to Hertz unit for frequency
1 rad/s = 0.1591
22.15rad/s=?
22.15 × 0.1591= 3.525 hertz
Answer is a) the force caused by the wend nag encountering wind and air.