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2 years ago

7. The lifetime of a certain brand of tires is approximately normally distributed, with a

Mathematics

1 answer:

Aleonysh [2.5K]2 years ago

7 0

Answer:

0.0025551

Step-by-step explanation:

Given that:

Mean (m) = 40000

Standard deviation (s) = 2500

P(x < 33,000) :

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (33000 - 40000) / 2500 = - 2.8

p(Z < -2.8) = 0.0025551 ( Z probability calculator)

Probability of Tyre wagering out before mileage limit is reached = 0.0025551

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1) Find the inverse of the function below. Use g-1(x) to indicate the inverse 5 points

omeli [17]

Answer:

g-1(x)=SQRT{(x-4)/2} + 4

Step-by-step explanation:

I assume that the 2 is the exponent so ^ represents exponent

We know your function is g(x)=2(x-3)^2+4

For inverse functions we swap x and y values, note g(x) is like the y value

Isolate for y

y=2(x-3)^2+4

x=2(y-3)^2+4

(x-4)/2 = (y-3)^2

SQRT{(x-4)/2} + 4 = y

Therefore g-1(x)=SQRT{(x-4)/2} + 4

4 0

2 years ago

Using elimination (combination), which variable will be eliminated first? 5x-y=-21x+y=-3

stiks02 [169]

Answer:

Option B) The variable Y will cancel out first.

Step-by-step explanation:

we have

5x-y=-21 ----> equation A

x+y=-3 ----> equation B

Solve by elimination

Adds equation A and equation B

5x-y=-21

x+y=-3

--------------

5x+x=-21-3 ----->variable y will be eliminated first

6x=-24

x=-4

7 0

2 years ago

How much warmer is it when the temperature is 17°F than when it is -11°F?

Rufina [12.5K]

Answer:

i thinks it -11°F but not sure

3 0

2 years ago

What is the sum of two numbers a and b decreased by their product?

belka [17]

The sum of two numbers a and b decreased by their product is (a+b)-ab

Step-by-step explanation:

Given the two numbers as a and b

Sum of these two numbers is a+b

The product of the two numbers is a*b, ab

The sum of the two numbers decreased by their product will be;

(a+b)-ab

Learn More

https://brainly.in/question/6082654
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Keywords : sum of two numbers, product

#LearnwithBrainly

8 0

2 years ago

Find the value of k so that 48x-ky=11 and (k+2)x+16y=-19 are perpendicular lines.

Rufina [12.5K]

Answer: k = -1 +/- √769

Step-by-step explanation:

48x - ky = 11

-48x -48x

-ky = -48x + 11

$\frac{-ky}{-k} = \frac{-48x}{-k} + \frac{11}{-k}$

$y =\frac{48x}{k} - \frac{11}{k}$

Slope: $\frac{48}{k}$

*************************************************************************

(k + 2)x + 16y = -19

- (k + 2)x -(k + 2)x

16y = -(k + 2)x - 19

$\frac{16y}{16} = -\frac{(k + 2)x}{16} - \frac{19}{16}$

$y = -\frac{(k + 2)x}{16} - \frac{19}{16}$

Slope: $-\frac{(k + 2)}{16}$

**********************************************************************************

$\frac{48}{k}$ and $-\frac{(k + 2)}{16}$ are perpendicular so they have opposite signs and are reciprocals of each other. When multiplied by its reciprocal, their product equals -1.

$-\frac{(k + 2)}{16}$ * $\frac{k}{48}$ = -1

$\frac{(k + 2)k}{16(48)}$ = 1

Cross multiply, then solve for the variable.

(k + 2)(k) = 16(48)

k² + 2k - 768 = 0

Use quadratic formula to solve:

k = -1 +/- √769

5 0

2 years ago