Part II: Find the sine, cosine, and tangent ratios of <y
1 answer:
Answer:
sin θ = 22.62°
cos θ = 22.62°
tan θ = 22.62°
Step-by-step explanation:
From the diagram above
Opposite = 5
Adjacent = 12
Hypotenuse = 13
a) sin θ = Opp/Hypotenuse
sin θ = 5/13
sin θ = 0.3846153846
arc sin 0.3846153846
= 22.619864948°
Approximately = 22.62°
b) cos θ = Adjacent/ Hypotenuse
θ = 12/13
= arccos(0.9230769230769231)
22.619864948°
Approximately = 22.62°
c) tan θ = Opposite/Adjacent
θ = 5/12
= arctan(0.4166666666666667)
= 22.619864948°
= 22.62°
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C) is the last one, the bottom one to be right